Matematika A - 2023./24. jesen, 23.

${\lim }_{x\to -2}f(x)=-1\backslash lim\; \_\{x\; \backslash rightarrow-2\}\; f(x)=-1$

${\lim }_{x\to 0}f(x)=3\backslash lim\; \_\{x\; \backslash rightarrow\; 0\}\; f(x)=3$

${\lim }_{x\to 1}f(x)=2\backslash lim\; \_\{x\; \backslash rightarrow\; 1\}\; f(x)=2$

${\lim }_{x\to 3}f(x)=0\backslash lim\; \_\{x\; \backslash rightarrow\; 3\}\; f(x)=0$